Questions from past MBA CET papers (31 to 40):

 

31. A thief hides his loot in a house. As the police chase him, he runs 2 kms to the west before taking a right turn and running for another 2 km. He then takes a right turn and runs for another 7 kms. Finally, he takes two right turns and runs 2 kms after taking each turn and defeats the police. How far must he walk in order to reach the house in which he had hidden the loot?

(a) 2 kms     (b) 3 kms     (c) 4 kms      (d) 1 km       (e) None of these

Solution: From his house, he walks 2 km west, 2 kms north, walks 7 km east, 2 km south, and 2 km west. Hence, the distance will be 5 – 2 = 3. Answer: 3 kms

 

32. If all the letters in the word WATCHDOG are rearranged as they appear in the English alphabet the position of how many letters will remain unchanged after the rearrangement?

(a) None       (b) One        (c) Two         (d) Three      (e) Four

Solution: Rearranging will give you only H at the same position.

W       A        T        C       H       D       O       G
A        C        D       G       H       O       T        W

Answer: One

 

Directions (Q.33-35): A, B, C, D, and E live in a six storey building (ground floor + five floors). Second floor of the building is vacant. B lives only above C. A lives immediately above E. D does not stay on the topmost floor.

33. Who of the following lives on the ground floor of the building?

(a) A             (b) B             (c) C             (d) D            (e) E

34. Who of the following lives immediately above the floor that is vacant?

(a) A            (b) B            (c) C            (d) D            (e) E

35. How many people live between B and A?

(a) None       (b) One        (c) Two         (d) Three      (e) Can not be determined

Solution: As B lives only above C, C has to be on the ground floor as there are 5 people and a floor is vacant. This will put B on the first floor. AE will always appear together with A above E and as D is not on the topmost floor, D will be on 3rd floor.

 

36. What should come in place of the question mark (?) in the following equation?

5169 + 3072 – (?) = 4924

(a) 3767       (b) 3947       (c) 3137       (d) 3317       (e) None of these

Solution: 5169 + 3072 = 8241 – 4924. Answer: 3317

 

37. What approximate value should come in place of the question mark (?) in the following equation?

2/7 of 1594 × 4.493 = ½ of (?)

(a) 4100       (b) 4800       (c) 3800       (d) 3400       (e) 4900

Solution: As the options are quite far from each other, easier to approximate. 1400 + 196 is completely divisible by 7, so let1594 be 1596. When divided by 7, it gives you 228. Double of which is 456. 456*4.5*2 = 456*9 ~ 4100. Answer: 4100

 

38. What should come in place of the question mark (?) in the following equation?

45% of 860 + (?) = 33.33% of 1500

(a) 143         (b) 83           (c) 113         (d) 123         (e) None of these

Solution: 1/3rd of 1500 = 500. 45% of 860 is (860/2 – 43) = 430 – 43 = 387. 500 – 387 will give you 113. Answer: 113

 

39. What approximate value should come in place of the question mark (?) in the following equation?

5376.12 ÷ 11.956 ÷ (?) = 55

(a) 8             (b) 6             (c) 10           (d) 12           (e) 4

Solution: 11.956 is close to 12. 5376/12 = 448. When 448/55, we get 8.something. Answer: 8

 

40. What approximate value should come in place of the question mark (?) in the following equation?

31% of 561.32 + 43% of 684.89 = (?)% of 1735.23

(a) 35           (b) 33           (c) 27           (d) 23           (e) 37

Solution: Approximate numbers. 30% of 560 = 168. 43% of 685 = (68.5*4 + 68.5/3) = 296.8 ~ 297

168 + 297 = 465. Now, 465/1735 = 93/347 = More than 25% but less than 33%. Answer: 27


P.S. – Preparing for MBA CET 2016? Attend a free CET workshop by Learningroots.
Date: 9th January 2016
Time: 5.30 pm onwards
Venue: Welingkar Institute of Management, Mumbai.
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